Calculus integration trigonometry ShareLegend x and y are independent variables, ;Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor

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Tan^2 + sec^2 = 1
Tan^2 + sec^2 = 1-Step 1 tan 2 x Simplify ————— xsec 2 Canceling Out 11 Canceling out x as it appears on both sides of the fraction line Equation at the end of step 1 tan 2 1 ———— sec 2 Step 2 Rewriting the whole as an Equivalent Fraction 21 Subtracting a fraction from a whole Rewrite the whole as a fraction using sec 2 as the denominator(2) 1 = cot(a) The left side is more complicated so start there tan(a) sec2(X) 1 = tan(x) Use a Pythagorean identity on the denominator = tan(3) Now you have = 2 Cancel = Now you have 3 Use a reciprocal identity



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Sin 2 (x) cos 2 (x) = 1 tan 2 (x) 1 = sec 2 (x) cot 2 (x) 1 = csc 2 (x) sin(x y) = sin x cos y cos x sin y cos(x y) = cos x cosy sin x sin yHence, testing if the `tan^2 x 1= sec^2 x` holds yields that it is a valid statement Approved by eNotes Editorial Team We'll help your grades soarThis article uses Greek letters such as alpha (α), beta (β), gamma (γ), and theta (θ) to represent anglesSeveral different units of angle measure are widely used, including degree, radian, and gradian () 1 full circle () = 360 degree = 2 π radian = 400 gonIf not specifically annotated by (°) for degree or for gradian, all values for angles in this article are assumed to be given in
Find the secant of the inverse tangent of 1/2 Find the secant of the inverse tangent of 1/2Cot (x) = cot (x) sin ^2 (x) cos ^2 (x) = 1 tan ^2 (x) 1 = sec ^2 (x) cot ^2 (x) 1 = csc ^2 (x) sin (x y) = sin x cos y cos x sin y cos (x y) = cos x cosy sin x sin y tan (x y) = (tan x tan y) / (1 tan x tan y) sin (2x) = 2 sin x cos x cos (2x) = cos ^2 (x) sin ^2 (x) = 2 cos ^2 (x) 1 = 1 2 sin ^2 (x)Answer to Integrate the trigonometric integral integral of sec^2(x)/(1tan(x)) dx evaluated from 0 to pi/4 By signing up, you'll get thousands of
Apr 12, 18 · Let m = tan^2(sec^12) cot^2(cosec^1 3) Then find the value of (m^2 m 10) asked Nov 9, 19 in Sets, relations and functions by SumanMandal ( 545k points)Sec tan 2 sec 2 1 sec tan sec 5 sec 2 y tan 5 sec 7 d SECTION 72 TRIGONOMETRIC from ENGINEERIN 10 at University of California, BerkeleyThe points labelled 1, Sec(θ), Csc(θ) represent the length of the line segment from the origin to that point Sin(θ), Tan(θ), and 1 are the heights to the line starting from the xaxis, while Cos(θ), 1, and Cot(θ) are lengths along the xaxis starting from the origin


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We have 1tan 2 = sec 2 1(3/4) 2 = sec 2 1(9/16) = sec 2 sec 2 = (169)/16 = 25/16 Taking square root on both sides sec = 5/4 We have cos = 1/sec cos = 1÷(5/4) cos = 4/5 Hence sec = 5/4 and cos = 4/5 3 If cot = 40/9 , find the values of cosec and sin Solution Given cot = 40/9 We have 1cot 2 = cosec 2We get (tan(x))2 1 = (sec(x))2 1 = (sec(x))2 (tan(x))2 Now, we will see if 1 = (sec(x))2 (tan(x))2and 1 = (sec(x))2 (tan(x))2 can both be true We can do this by assuming that they are both true, and then add the equations to get 2 = 2(sec(x))2 1=(sec(x))2Find all solutions of sec^2xtan^2x=3 in the interval 0,2piSince tan^2 = sec^2 1 you getsec^2 sec^21 = 3 2sec^2= 4 sec^2 = 2



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May 21, 18 · because tan^2 45 = 1^2 = 1 and sec^2 x = 1/ cos^2 45 = (sqrt2)^2 = 2 so the sum = 3 coolbun coolbun Answer the answer is false Stepbystep explanation apex New questions in Mathematics surface area of B is 4032 surface area of a is 28 TEST II COMBINATIONDIRECTION SOLVE THE FOLLOWING USING COMBINATION1)L H S = tan 2 A cot 2 A = sin 2 A cos 2 A 1 − 2 sin 2 A cos 2 A = c o s 2 A 1 s i n 2 A 1 − 2 = sec 2 A c o s e c 2 A − 2Integral tan^2(x)sec(x)powers of secant and tangent



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Mar 19, 18 · See Below Left Hand Side sec^2(x)tan^2x =1/cos^2x (sin^2x)/cos^2x =(1sin^2x)/cos^2x =cos^2x/cos^2x> Use Property sin^2xcos^2x=1 and isolate cos^2x =cancel(cos^2x/cos^2x =1 = Right Hand Side TrigonometryProve sec^2(x)tan^2(x)=1 Let us prove the equation We know the identity sin 2 (x)cos 2 (x)=1 ——(i) Dividing throughout the equation by cos 2 (x) We get sin 2 (x)/cos 2 (x) cos 2 (x)/cos 2 (x) = 1/cos 2 (x) We know that sin 2 (x)/cos 2 (x)= tan 2 (x), and cos 2 (x)/cos 2 (x) = 1 So the equation (i) after substituting becomesYou can put this solution on YOUR website!


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Apr 28, 18 · Explanation Let θ = tan−1(2) ⇒ tanθ = 2 We know 1 tan2θ = sec2θ ⇒ 1 22 = sec2θ ⇒ sec2θ = 5 ⇒ secθ = √5 ⇒ sec(tan−1(2)) = √5∫{sec^2 x / (sec x tan x)^9/2} dx = (for some arbitrary constant c)An expansion of Pythagoras' Identity



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